2c^2+17c+35=

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Solution for 2c^2+17c+35= equation:


Simplifying
2c2 + 17c + 35 = 0

Reorder the terms:
35 + 17c + 2c2 = 0

Solving
35 + 17c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + c)(7 + 2c) = 0

Subproblem 1

Set the factor '(5 + c)' equal to zero and attempt to solve: Simplifying 5 + c = 0 Solving 5 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + c = 0 + -5 c = 0 + -5 Combine like terms: 0 + -5 = -5 c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(7 + 2c)' equal to zero and attempt to solve: Simplifying 7 + 2c = 0 Solving 7 + 2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 2c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 2c = 0 + -7 2c = 0 + -7 Combine like terms: 0 + -7 = -7 2c = -7 Divide each side by '2'. c = -3.5 Simplifying c = -3.5

Solution

c = {-5, -3.5}

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